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A060645 a(0) = 0, a(1) = 4 then a(n) = 18*a(n-1)-a(n-2). 6
0, 4, 72, 1292, 23184, 416020, 7465176, 133957148, 2403763488, 43133785636, 774004377960, 13888945017644, 249227005939632, 4472197161895732, 80250321908183544, 1440033597185408060, 25840354427429161536 (list; graph; refs; listen; history; internal format)
OFFSET

0,2

COMMENTS

a(n) = 18*a(n-1) - a(n-2), with a(1) = denominator of continued fraction [2;4] and a(2) = denominator of [2;4,4,4].

a(n) solves for y in the Diophantine equation x^2 - 5*y^2 = 1, the third simplest case of the Pell-Fermat type. The corresponding x solutions are provided by A023039.

n such that 5*n^2=floor(sqrt(5)*n*ceil(sqrt(5)*n)) Benoit Cloitre (benoit7848c(AT)orange.fr), May 10 2003

LINKS

Harry J. Smith, Table of n, a(n) for n = 0..200

Tanya Khovanova, Recursive Sequences

John Robertson, Home page.

Index to sequences with linear recurrences with constant coefficients, signature (18,-1).

FORMULA

G.f.: 4x/(1-18*x+x^2). - Cino Hilliard (hillcino368(AT)gmail.com), Feb 02 2006

a(n) may be computed either as i) the denominator of the (2n-1)-th convergent of the continued fraction [2;4, 4, 4, ...] = sqrt(5), or ii) as the coefficient of sqrt(5) in {9+sqrt(5)}^n.

n such that Mod(sigma(5*n^2+1), 2 ) = 1 - Mohammed Bouayoun (bouyao(AT)wanadoo.fr), Mar 26 2004

a(n)=4*A049660(n), a(n)=A000045(6*n)/2. - Benoit Cloitre (benoit7848c(AT)orange.fr), Feb 03 2006

a(n) = 17*(a(n-1)+a(n-2))-a(n-3), a(n) = 19*(a(n-1)-a(n-2))+a(n-3). - Mohamed Bouhamida (bhmd95(AT)yahoo.fr), Sep 20 2006

a(n)=-(1/10)*[9-4*sqrt(5)]^n*sqrt(5)+(1/10)*sqrt(5)*[9+4*sqrt(5)]^n, with n>=0 [From Paolo P. Lava (paoloplava(AT)gmail.com), Oct 02 2008]

Contribution from Johannes W. Meijer (meijgia(AT)hotmail.com), Jul 01 2010: (Start)

Limit(a(n+k)/a(k), k=infinity) = A023039(n) + A060645(n)*sqrt(5)

Limit(A023039(n)/a(n), n=infinity) = sqrt(5)

(End)

EXAMPLE

Given a(1) = 4, a(2) = 72 we have for instance a(4) = 18*a(3) - a(2) = 18*{18*a(2) -a(1)} - a(2), i.e. a(4) = 323*a(2) - 18*a(1) = 323*72 - 18*4 = 23184.

MAPLE

A060645 := proc(n) option remember: if n=1 then RETURN(4) fi: if n=2 then RETURN(72) fi: 18*A060645(n -1)- A060645(n-2): end: for n from 1 to 30 do printf(`%d, `, A060645(n)) od:

MATHEMATICA

CoefficientList[ Series[4x/(1 - 18x + x^2), {x, 0, 16}], x] (* Robert G. Wilson v *)

Select[Select[Table[Fibonacci[n], {n, 0, 5!}], EvenQ]/2, EvenQ] [From Vladimir Orlovsky (4vladimir(AT)gmail.com), May 10 2010]

LinearRecurrence[{18, -1} {0, 4}, 50] (* Sture Sjöstedt Nov 29 2011 *)

PROG

(PARI) g(n, k) = for(y=0, n, x=k*y^2+1; if(issquare(x), print1(y", ")))

(PARI) a(n)=fibonacci(6*n)/2 (Cloitre)

(PARI) for (i=1, 10000, if(Mod(sigma(5*i^2+1), 2)==1, print1(i, ", ")))

(PARI) { for (n=0, 200, write("b060645.txt", n, " ", fibonacci(6*n)/2); ) } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Jul 09 2009]

CROSSREFS

Cf. A023039.

Sequence in context: A165212 A100521 A111868 * A203073 A201976 A176901

Adjacent sequences:  A060642 A060643 A060644 * A060646 A060647 A060648

KEYWORD

nonn,easy

AUTHOR

Lekraj Beedassy (blekraj(AT)yahoo.com), Apr 17 2001

EXTENSIONS

More terms from James A. Sellers (sellersj(AT)math.psu.edu), Apr 19 2001

Entry revised by N. J. A. Sloane (njas(AT)research.att.com), Aug 13 2006

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Last modified February 14 03:37 EST 2012. Contains 205570 sequences.