1,1
C. Rivera, Prime Puzzles
For n = 2 we have 3*4 = 5*6*7 = 1 mod 11. For n = 3 we have 2*3*4*5 = 6*7*8*9*10*11 = 12*13*14*15 = 1 mod 17.
Sequence in context: A133410 A156829 A105840 * A108894 A066794 A087379
Adjacent sequences: A060424 A060425 A060426 * A060428 A060429 A060430
nonn,nice
Jason Earls (zevi_35711(AT)yahoo.com), Apr 05 2001
More terms from Jens Kruse Andersen (jens.k.a(AT)get2net.dk), May 04 2007