OFFSET
1,2
COMMENTS
A cubefree word. Start with 1, apply the morphisms 1 -> 121, 2 -> 122, take limit. See A080846 for another version.
Ultimate modulo 3: n-th digit of terms in "Ana sequence" (see A060032 for definition).
Equals A005148(n) reduced mod 3. In "On a sequence Arising in Series for Pi" Morris Newman and Daniel Shanks conjectured that 3 never divides A005148(n) and D. Zagier proved it. - Benoit Cloitre, Jun 22 2002
Also equals A038502(n) mod 3.
Last nonzero digit in ternary representation of n. - Franklin T. Adams-Watters, Apr 01 2006
a(2*n) = length of n-th run of twos. - Reinhard Zumkeller, Mar 13 2015
LINKS
Reinhard Zumkeller, Table of n, a(n) for n = 1..1000
Jean Berstel and J. Karhumaki, Combinatorics on words - a tutorial, Bull. EATCS, #79 (2003), pp. 178-228.
FORMULA
a(3*n) = a(n), a(3*n + 1) = 1, a(3*n + 2) = 2. - Michael Somos, Jul 29 2009
a(n) = 1 + A080846(n). - Joerg Arndt, Jan 21 2013
EXAMPLE
a(10)=1 since 10=3^0*10 and 10 mod 3=1;
a(72)=2 since 24=3^3*8 and 8 mod 3=2.
MATHEMATICA
Nest[ Flatten[ # /. {1 -> {1, 2, 1}, 2 -> {1, 2, 2}}] &, {1}, 5] (* Robert G. Wilson v, Mar 04 2005 *)
Table[Mod[n/3^IntegerExponent[n, 3], 3], {n, 1, 120}] (* Clark Kimberling, Oct 19 2016 *)
lnzd[m_]:=Module[{s=Split[m]}, If[FreeQ[Last[s], 0], s[[-1, 1]], s[[-2, 1]]]]; lnzd/@Table[IntegerDigits[n, 3], {n, 120}] (* Harvey P. Dale, Oct 19 2018 *)
PROG
(PARI) a(n)=if(n<1, 0, n/3^valuation(n, 3)%3) /* Michael Somos, Nov 10 2005 */
(Haskell) following Franklin T. Adams-Watters's comment.
a060236 = head . dropWhile (== 0) . a030341_row
-- Reinhard Zumkeller, Mar 13 2015
(Magma) [(Floor(n/3^Valuation(n, 3)) mod 3): n in [1..120]]; // G. C. Greubel, Nov 05 2024
(SageMath) [n/3^valuation(n, 3)%3 for n in range(1, 121)] # G. C. Greubel, Nov 05 2024
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Henry Bottomley, Mar 21 2001
STATUS
approved