%I #13 Apr 27 2023 10:26:46
%S 1,2,20,345,10104,450450,28480140,2423938845,267208852820,
%T 37037118818700,6304443126648900,1292877846962865230,
%U 314390193022547991720,89447117243116404721950,29436259549934873636908816,11094961973721205588579579845,4748429366816935180127543967840
%N Number of orbits of length n under the map whose periodic points are counted by A000364.
%C The sequence A000364 seems to record the number of points of period n under a map. The number of orbits of length n for this map gives the sequence above.
%H Alois P. Heinz, <a href="/A060164/b060164.txt">Table of n, a(n) for n = 1..243</a>
%H Y. Puri and T. Ward, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL4/WARD/short.html">Arithmetic and growth of periodic orbits</a>, J. Integer Seqs., Vol. 4 (2001), #01.2.1.
%H Yash Puri and Thomas Ward, <a href="http://www.fq.math.ca/Scanned/39-5/puri.pdf">A dynamical property unique to the Lucas sequence</a>, Fibonacci Quarterly, Volume 39, Number 5 (November 2001), pp. 398-402.
%F a(n) = (1/n)* Sum_{d|n} mu(d)*A000364(n/d).
%e u(3) = 20 since the conjectured map whose periodic points are counted by A000364 would have 1 fixed point and 61 points of period 3, so it must have 20 orbits of length 3.
%Y Cf. A000364, A060165, A060166, A060167, A060168, A060169, A060170, A060171, A060172, A060173.
%K easy,nonn
%O 1,2
%A _Thomas Ward_, Mar 13 2001
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