%I #11 Jun 13 2017 11:57:07
%S 1,9,61,143,159,387,1137,1973,3337,16895,37171
%N Numbers n such that n^2*2^n + n*2^((n + 1)/2) + 1 is prime.
%D Posting to NMBRTHRY(AT)LISTSERV.NODAK.EDU by _Mike Oakes_ Dec 30 2000 entitled "Gaussian analogues of the Cullen and Woodall primes."
%H <a href="/index/Ga#gaussians">Index entries for Gaussian integers and primes</a>
%t Do[ If[ PrimeQ[ n^2*2^n + n*2^((n + 1)/2) + 1], Print[n] ], {n, 1, 50000} ]
%o (PARI) is(n)=ispseudoprime(n^2*2^n+n*2^((n+1)/2)+1) \\ _Charles R Greathouse IV_, Jun 13 2017
%K nonn
%O 1,2
%A _Robert G. Wilson v_, Jan 02 2001