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A057431
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Obtained by reading first numerator then denominator of fractions in full Stern-Brocot tree (A007305/A047679).
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2
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0, 1, 1, 0, 1, 1, 1, 2, 2, 1, 1, 3, 2, 3, 3, 2, 3, 1, 1, 4, 2, 5, 3, 5, 3, 4, 4, 3, 5, 3, 5, 2, 4, 1, 1, 5, 2, 7, 3, 8, 3, 7, 4, 7, 5, 8, 5, 7, 4, 5, 5, 4, 7, 5, 8, 5, 7, 4, 7, 3, 8, 3, 7, 2, 5, 1, 1, 6, 2, 9, 3, 11, 3, 10, 4, 11, 5, 13, 5, 12, 4, 9, 5, 9, 7, 12, 8, 13, 7, 11, 7, 10, 8, 11, 7, 9, 5, 6, 6, 5
(list; graph; refs; listen; history; internal format)
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OFFSET
| 0,8
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COMMENTS
| When presented in this way, every row (e.g. row 3, 1 3 2 3 3 2 3 1) is a palindrome. - Joshua Zucker (joshua.zucker(AT)stanfordalumni.org), May 11 2006
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LINKS
| N. J. A. Sloane, Stern-Brocot or Farey Tree
Index entries for sequences related to Stern's sequences
Alois P. Heinz, Table of n, a(n) for n = 0..10000
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MAPLE
| F:= proc(n) option remember; local t;
t:= l-> [[l[1], [l[1][1]+l[2][1], l[1][2]+l[2][2]], l[2]],
[l[2], [l[2][1]+l[3][1], l[2][2]+l[3][2]], l[3]]][];
if n=0 then [[[ ], [0, 1], [ ]], [[ ], [1, 0], [ ]]]
elif n=1 then [[[0, 1], [1, 1], [1, 0]]]
else map (t, F(n-1))
fi
end:
aa:= n-> map (x->x[], [seq (map (x->x[2], F(j))[], j=0..n)])[]:
aa(7); # aa(n) gives the first 2^(n+1)+2 terms
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CROSSREFS
| Cf. A007305, A047679, A007306, A002487, A057432.
Sequence in context: A125778 A047110 A093869 * A179541 A057060 A198380
Adjacent sequences: A057428 A057429 A057430 * A057432 A057433 A057434
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KEYWORD
| nonn,easy
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AUTHOR
| N. J. A. Sloane (njas(AT)research.att.com), Sep 08 2000
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EXTENSIONS
| More terms from Joshua Zucker (joshua.zucker(AT)stanfordalumni.org), May 11 2006
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