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1) Write n in binary; 2) Find run lengths of this expression; 3) Replace these as follows: 1 -> 0, 2 -> 010, 3 -> 01010, 4 -> 0101010...; 4) Remove final 0 and append an initial 1; 5) The term a(n) is the number with the obtained Zeckendorf expression.
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%I #5 Aug 18 2020 15:42:15

%S 1,2,4,6,3,7,12,17,10,5,9,19,11,20,33,46,28,16,27,14,8,15,25,51,31,18,

%T 30,53,32,54,88,122,75,45,74,43,26,44,72,38,23,13,22,40,24,41,67,135,

%U 83,50,82,48,29,49,80,140,86,52,85,142,87,143,232,321,198,121,197,119

%N 1) Write n in binary; 2) Find run lengths of this expression; 3) Replace these as follows: 1 -> 0, 2 -> 010, 3 -> 01010, 4 -> 0101010...; 4) Remove final 0 and append an initial 1; 5) The term a(n) is the number with the obtained Zeckendorf expression.

%C A permutation of the positive integers.

%e a(24) = 51 because: 1) 24 in binary is 11000 2) the run lengths are 2, 3 3) 01001010 4) 10100101 5) the Zeckendorf expression of 51 is 10100101 because 51 = 34 + 13 + 3 + 1

%Y Inverse of A057337.

%K nonn

%O 1,2

%A _Alex Fink_, Aug 27 2000

%E More terms from _David W. Wilson_, May 12 2001