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a(n-1)+k=a(n) => a(n)^k=a(n+1).
1

%I #2 May 20 2014 14:52:31

%S 1,3,9,531441

%N a(n-1)+k=a(n) => a(n)^k=a(n+1).

%C For +k and *k see A057268.

%Y Cf. A057268.

%K easy,nonn

%O 0,2

%A _Jonas Wallgren_, Aug 22 2000