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A056674 Number of squarefree divisors which are not unitary. Also number of unitary divisors which are not squarefree. 3

%I #23 Apr 21 2021 07:13:46

%S 0,0,0,1,0,0,0,1,1,0,0,2,0,0,0,1,0,2,0,2,0,0,0,2,1,0,1,2,0,0,0,1,0,0,

%T 0,3,0,0,0,2,0,0,0,2,2,0,0,2,1,2,0,2,0,2,0,2,0,0,0,4,0,0,2,1,0,0,0,2,

%U 0,0,0,3,0,0,2,2,0,0,0,2,1,0,0,4,0,0,0,2,0,4,0,2,0,0,0,2,0,2,2,3,0,0,0,2,0

%N Number of squarefree divisors which are not unitary. Also number of unitary divisors which are not squarefree.

%C Numbers of unitary and of squarefree divisors are identical, although the 2 sets are usually different, so sizes of parts outside overlap are also equal to each other.

%H Antti Karttunen, <a href="/A056674/b056674.txt">Table of n, a(n) for n = 1..10000</a>

%H <a href="/index/Eu#epf">Index entries for sequences computed from exponents in factorization of n</a>

%F a(n) = A034444(n) - A056671(n) = A034444(n) - A000005(A055231(n)) = A034444(n) - A000005(A007913(n)/A055229(n)).

%e n=252, it has 18 divisors, 8 are unitary, 8 are squarefree, 2 belong to both classes, so 6 are squarefree but not unitary, thus a(252)=6. Set {2,3,14,21,42} forms squarefree but non-unitary while set {4,9,36,28,63,252} of same size gives the set of not squarefree but unitary divisors.

%t Table[DivisorSum[n, 1 &, And[SquareFreeQ@ #, ! CoprimeQ[#, n/#]] &], {n, 105}] (* _Michael De Vlieger_, Jul 19 2017 *)

%o (PARI)

%o A034444(n) = (2^omega(n));

%o A057521(n) = { my(f=factor(n)); prod(i=1, #f~, if(f[i, 2]>1, f[i, 1]^f[i, 2], 1)); } \\ _Charles R Greathouse IV_, Aug 13 2013

%o A055231(n) = n/A057521(n);

%o A056674(n) = (A034444(n) - numdiv(A055231(n)));

%o \\ Or:

%o A055229(n) = { my(c=core(n)); gcd(c, n/c); }; \\ _Charles R Greathouse IV_, Nov 20 2012

%o A056674(n) = ((2^omega(n)) - numdiv(core(n)/A055229(n)));

%o \\ _Antti Karttunen_, Jul 19 2017

%o (Python)

%o from sympy import gcd, primefactors, divisor_count

%o from sympy.ntheory.factor_ import core

%o def a055229(n):

%o c=core(n)

%o return gcd(c, n//c)

%o def a056674(n): return 2**len(primefactors(n)) - divisor_count(core(n)//a055229(n))

%o print([a056674(n) for n in range(1, 101)]) # _Indranil Ghosh_, Jul 19 2017

%Y Cf. A000005, A007913, A034444, A000005, A055231, A055229, A056671.

%K nonn

%O 1,12

%A _Labos Elemer_, Aug 10 2000

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Last modified April 19 10:56 EDT 2024. Contains 371791 sequences. (Running on oeis4.)