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%I #9 Dec 12 2021 19:47:19
%S 1,10,11,28,29,54,55,82,83,88,89,130,131,152,153,180,181,218,219,250,
%T 251,278,279,304,305,310,311,338,339,372,373,378,379,406,407,416,417,
%U 418,419,438,439,454,455,460,461,474,475,530,531,550,551,596,597,614
%N Numbers k such that k! is divisible by the square of (f+d)!^2 for d=0 and d=1 (and possibly larger d), where f = floor(k/2).
%C Observe that all terms (except 1) are pairs of consecutive numbers starting with an even number (e.g., 88, 89).
%e For n=10 and 11, 10! or 11! are divided both by 5!^2 and 6!^2.
%Y Cf. A056038-A056044, A056068.
%K nonn
%O 1,2
%A _Labos Elemer_, Jul 26 2000
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