OFFSET
0,7
COMMENTS
With a(0)=0, a(1)=1, a(2)=1, a(3)=2, a(4)=4, a(5)=7, this recurrence produces a(n) = A000073(n+1) (tribonacci numbers).
LINKS
Index entries for linear recurrences with constant coefficients, signature (6,-5,-4,-3,2,1).
FORMULA
O.g.f.: -x^5/((x^3+x^2-5*x+1)*(x^3+x^2+x-1)). - R. J. Mathar, Nov 23 2007
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Asher Auel, Jun 06 2000
EXTENSIONS
New name, from formula, added by Michel Marcus, Mar 19 2024
STATUS
approved