|
|
A055958
|
|
a(n) = n + reversal of base 9 digits of n (written in base 10).
|
|
3
|
|
|
0, 2, 4, 6, 8, 10, 12, 14, 16, 10, 20, 30, 40, 50, 60, 70, 80, 90, 20, 30, 40, 50, 60, 70, 80, 90, 100, 30, 40, 50, 60, 70, 80, 90, 100, 110, 40, 50, 60, 70, 80, 90, 100, 110, 120, 50, 60, 70, 80, 90, 100, 110, 120, 130, 60, 70, 80, 90, 100, 110, 120, 130, 140, 70, 80, 90
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,2
|
|
COMMENTS
|
If n has an even number of digits in base 9 then a(n) is a multiple of 10
|
|
LINKS
|
|
|
FORMULA
|
|
|
MATHEMATICA
|
Table[n+FromDigits[Reverse[IntegerDigits[n, 9]], 9], {n, 0, 70}] (* Harvey P. Dale, Sep 03 2013 *)
|
|
PROG
|
(PARI) a(n) = n + fromdigits(Vecrev(digits(n, 9)), 9); \\ Michel Marcus, Sep 27 2018
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|