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a(n) = n + reversal of base 5 digits of n (written in base 10).
3

%I #13 Aug 07 2024 15:35:54

%S 0,2,4,6,8,6,12,18,24,30,12,18,24,30,36,18,24,30,36,42,24,30,36,42,48,

%T 26,52,78,104,130,36,62,88,114,140,46,72,98,124,150,56,82,108,134,160,

%U 66,92,118,144,170,52,78,104,130,156,62,88,114,140,166,72,98,124,150

%N a(n) = n + reversal of base 5 digits of n (written in base 10).

%C If n has an even number of digits in base 5 then a(n) is a multiple of 6.

%H Seiichi Manyama, <a href="/A055950/b055950.txt">Table of n, a(n) for n = 0..10000</a>

%F a(n) = n + A030104(n).

%t Table[n + IntegerReverse[n, 5], {n, 0, 100}] (* _Paolo Xausa_, Aug 07 2024 *)

%Y Cf. A030104, A056964.

%K base,nonn,look

%O 0,2

%A _Henry Bottomley_, Jul 18 2000