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%I #12 Oct 26 2019 02:07:43
%S 1,1,2,4,2,10,2,22,2,46,2,72,2,168,2,88,2,428,2,858,2,620,2,2294,2,
%T 4006,2,7546,2,16192,2,29472,2,7442,2,60960,2,127972,2,38738,2,296980,
%U 2,593962,2,798786,2,1986714,2,3926978,2,5023380,2,12923792,2,16513952
%N a(0)=1; a(n) = Sum_{j<n, gcd(n,a(j)) = 1} a(j).
%C For j > 0, a(2j) = 2 and a(j+1) is even.
%e a(9) = 46 because all previous terms are relatively prime to 9 and the sum of all previous terms is 46.
%K easy,nonn
%O 0,3
%A _Leroy Quet_, Jul 17 2000
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