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A055187
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Cumulative counting sequence: method A (adjective,noun)-pairs with first term 1.
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3
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1, 1, 1, 3, 1, 4, 1, 1, 3, 6, 1, 2, 3, 1, 4, 8, 1, 1, 2, 3, 3, 2, 4, 1, 6, 11, 1, 3, 2, 5, 3, 3, 4, 2, 6, 1, 8, 13, 1, 5, 2, 8, 3, 4, 4, 1, 5, 3, 6, 2, 8, 1, 11, 16, 1, 7, 2, 10, 3, 6, 4, 3, 5, 4, 6, 4, 8, 2, 11, 1, 13, 18, 1, 9, 2, 12, 3, 9, 4, 4, 5, 6, 6, 1, 7, 5, 8, 1, 10, 3, 11, 2, 13, 1, 16, 22, 1
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,4
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COMMENTS
| Conjecture: every nonnegative integer occurs.
Conjectures: limit as n goes to infinity of max {a(k) : 1<=k<=n}/sqrt(n) = 2;
-3 < a(n) - 2*sqrt(n) < 3 for all n;
there are infinitely many n such that a(n)=a(n+1). - Benoit Cloitre (benoit7848c(AT)orange.fr), Jan 30 2003
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EXAMPLE
| Segments: 1; 1,1; 3,1; 4,1,1,3; 6,1,2,3,1,4; ...
Write 1, thus having 1 1, thus having 3 1's, thus having 4 1's and 1 3, etc.
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CROSSREFS
| Cf. A055186.
Sequence in context: A079668 A144211 A125291 * A109411 A130307 A130314
Adjacent sequences: A055184 A055185 A055186 * A055188 A055189 A055190
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KEYWORD
| nonn
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AUTHOR
| Clark Kimberling (ck6(AT)evansville.edu), Apr 27 2000
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EXTENSIONS
| Corrected and extended by Benoit Cloitre (benoit7848c(AT)orange.fr), Jan 30 2003
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