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A054763 Residues of consecutive prime differences modulo 6. 5
1, 2, 2, 4, 2, 4, 2, 4, 0, 2, 0, 4, 2, 4, 0, 0, 2, 0, 4, 2, 0, 4, 0, 2, 4, 2, 4, 2, 4, 2, 4, 0, 2, 4, 2, 0, 0, 4, 0, 0, 2, 4, 2, 4, 2, 0, 0, 4, 2, 4, 0, 2, 4, 0, 0, 0, 2, 0, 4, 2, 4, 2, 4, 2, 4, 2, 0, 4, 2, 4, 0, 2, 0, 0, 4, 0, 2, 4, 2, 4, 2, 4, 2, 0, 4, 0, 2, 4, 2, 4, 0, 2, 4, 2, 4, 0, 0, 2, 0, 0, 4, 0, 0, 2, 0 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
For n>2, only the 0-residues may arise several times after each other, that is, there are no "2,2" and no "4,4". Let nz(k) denote the nonzero values of A054763(n). Then nz(0)=1, nz(1)=2, nz(2)=2, and nz(k+1)=6-nz(k) for k>1. Conjecture: the percentage of zeros in A054763(n) asymptotically runs to 50%. - Alex Ratushnyak, Apr 18 2012
LINKS
FORMULA
a(n) = A001223(n) mod 6.
MATHEMATICA
Mod[#, 6] & /@ Differences@ Prime@ Range@ 105 (* Michael De Vlieger, Mar 05 2017 *)
PROG
(PARI) a(n) = (prime(n+1) - prime(n)) % 6; \\ Michel Marcus, Dec 17 2013
CROSSREFS
Cf. A001223.
Sequence in context: A248913 A227951 A102641 * A100374 A045841 A040003
KEYWORD
nonn
AUTHOR
Labos Elemer, May 17 2000
STATUS
approved

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Last modified April 23 03:30 EDT 2024. Contains 371906 sequences. (Running on oeis4.)