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A054763
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Residues of consecutive prime differences modulo 6.
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5
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1, 2, 2, 4, 2, 4, 2, 4, 0, 2, 0, 4, 2, 4, 0, 0, 2, 0, 4, 2, 0, 4, 0, 2, 4, 2, 4, 2, 4, 2, 4, 0, 2, 4, 2, 0, 0, 4, 0, 0, 2, 4, 2, 4, 2, 0, 0, 4, 2, 4, 0, 2, 4, 0, 0, 0, 2, 0, 4, 2, 4, 2, 4, 2, 4, 2, 0, 4, 2, 4, 0, 2, 0, 0, 4, 0, 2, 4, 2, 4, 2, 4, 2, 0, 4, 0, 2, 4, 2, 4, 0, 2, 4, 2, 4, 0, 0, 2, 0, 0, 4, 0, 0, 2, 0
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OFFSET
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1,2
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COMMENTS
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For n>2, only the 0-residues may arise several times after each other, that is, there are no "2,2" and no "4,4". Let nz(k) denote the nonzero values of A054763(n). Then nz(0)=1, nz(1)=2, nz(2)=2, and nz(k+1)=6-nz(k) for k>1. Conjecture: the percentage of zeros in A054763(n) asymptotically runs to 50%. - Alex Ratushnyak, Apr 18 2012
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LINKS
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FORMULA
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MATHEMATICA
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PROG
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(PARI) a(n) = (prime(n+1) - prime(n)) % 6; \\ Michel Marcus, Dec 17 2013
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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