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A053838
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(Sum of digits of n written in base 3) modulo 3.
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9
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0, 1, 2, 1, 2, 0, 2, 0, 1, 1, 2, 0, 2, 0, 1, 0, 1, 2, 2, 0, 1, 0, 1, 2, 1, 2, 0, 1, 2, 0, 2, 0, 1, 0, 1, 2, 2, 0, 1, 0, 1, 2, 1, 2, 0, 0, 1, 2, 1, 2, 0, 2, 0, 1, 2, 0, 1, 0, 1, 2, 1, 2, 0, 0, 1, 2, 1, 2, 0, 2, 0, 1, 1, 2, 0, 2, 0, 1, 0, 1, 2, 1, 2, 0, 2, 0, 1, 0, 1, 2, 2, 0, 1, 0, 1, 2, 1, 2, 0, 0, 1, 2, 1, 2, 0
(list; graph; refs; listen; history; internal format)
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OFFSET
| 0,3
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COMMENTS
| Equals A004128, (0, 1, 2, 4, 5, 6, 8, 9, 10,...) mod 3 [From Gary W. Adamson (qntmpkt(AT)yahoo.com), Aug 24 2008]
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LINKS
| Michael Gilleland, Some Self-Similar Integer Sequences
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FORMULA
| a(n) =A010872(A053735(n)) =(n+a(floor[n/3])) mod 3. So can construct sequence by starting with 0 and mapping 0->012, 1->120 and 2->201 (e.g. 0, 012, 012120201, 012120201120201012201012120, ...) and looking at n-th digit of a term with sufficient digits.
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MATHEMATICA
| Nest[ Flatten[ # /. {0 -> {0, 1, 2}, 1 -> {1, 2, 0}, 2 -> {2, 0, 1}}] &, {0}, 7] (from Robert G. Wilson v Mar 08 2005).
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CROSSREFS
| Cf. A010060, A053837, A053839-A053844.
Equals A026600(n+1) - 1.
A004128 [From Gary W. Adamson (qntmpkt(AT)yahoo.com), Aug 24 2008]
Sequence in context: A118233 A181117 A159955 * A117167 A117169 A046920
Adjacent sequences: A053835 A053836 A053837 * A053839 A053840 A053841
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KEYWORD
| base,nonn
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AUTHOR
| Henry Bottomley (se16(AT)btinternet.com), Mar 28 2000
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