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A053665
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Smallest number m such that m = j^2 (mod prime(j)) for 1 <= j <= n.
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1
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1, 1, 19, 79, 289, 18769, 198949, 6325069, 103321969, 1218786319, 98264184769, 3708353007109, 226330497051409, 2964582868796299, 120709434853826569, 21641851825451025919, 738603338323632009979
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OFFSET
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1,3
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LINKS
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EXAMPLE
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a(3) = 19 because this is the smallest number m such that m = 1^2 (mod 2), m = 2^2 (mod 3) and m = 3^2 (mod 5).
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MATHEMATICA
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Array[ChineseRemainder @@ Transpose@ Map[{#^2, Prime[#]} &, Range[#]] &, 17] (* Michael De Vlieger, Jan 14 2022 *)
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PROG
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(PARI) okm(m, n) = {for (i=1, n, pi = prime(i); if ((m % pi) != (i^2 % pi), return (0)); ); return (1); }
a(n) = {m = 1; while (! okm(m, n), m++); m; } \\ Michel Marcus, Sep 02 2013
(PARI) x=Mod(1, 1); for(i=1, 17, x=chinese(x, Mod(i * i, prime(i))); print1(component(x, 2), ", ")) \\ Sean A. Irvine, Jan 11 2022
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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Joe K. Crump (joecr(AT)carolina.rr.com), Feb 16 2000
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STATUS
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approved
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