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a(n)=[A*a(n-1)+B*a(n-2)+C]/p^r, where p^r is the highest power of p dividing [A*a(n-1)+B*a(n-2)+C], A=1.0001, B=1.0001, C=1.5, p=2.
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%I #10 Apr 19 2016 01:07:32

%S 1,1,3,5,9,15,25,41,67,109,177,287,465,753,1219,1973,3193,323,3517,

%T 3841,115,3957,4073,251,4325,4577,1113,1423,2537,3961,1625,1397,3023,

%U 4421,3723,4073,3899,3987,493,4481,4975,4729,4853,599,2727,3327,757

%N a(n)=[A*a(n-1)+B*a(n-2)+C]/p^r, where p^r is the highest power of p dividing [A*a(n-1)+B*a(n-2)+C], A=1.0001, B=1.0001, C=1.5, p=2.

%C At the 10087th term, the sequence becomes cyclic with period 10086.

%Y Cf. A053521, A053523, A028948.

%K nonn

%O 1,3

%A _Yasutoshi Kohmoto_