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A053088 a(n) = 3*a(n-2) + 2*a(n-3) for n > 2, a(0)=1, a(1)=0, a(2)=3. 12

%I #100 Mar 30 2024 21:19:39

%S 1,0,3,2,9,12,31,54,117,224,459,906,1825,3636,7287,14558,29133,58248,

%T 116515,233010,466041,932060,1864143,3728262,7456549,14913072,

%U 29826171,59652314,119304657,238609284,477218599,954437166,1908874365

%N a(n) = 3*a(n-2) + 2*a(n-3) for n > 2, a(0)=1, a(1)=0, a(2)=3.

%C Growth of happy bug population in GCSE math course work assignment.

%C The generalized (3,2)-Padovan sequence p(3,2;n). See the W. Lang link under A000931. - _Wolfdieter Lang_, Jun 25 2010

%C With offset 1: a(n) = -2^n*Sum_{k=0..n} k^p*q^k for p=1, q=-1/2. See also A232603 (p=2, q=-1/2), A232604 (p=3, q=-1/2). - _Stanislav Sykora_, Nov 27 2013

%C From _Paul Curtz_, Nov 02 2021 (Start)

%C a(n-2) difference table (from 0, 0, a(n)):

%C 0 0 1 0 3 2 9 12 31 54 ...

%C 0 1 -1 3 -1 7 3 19 23 63 ...

%C 1 -2 4 -4 8 -4 16 4 40 44 ...

%C -3 6 -8 12 -12 20 -12 36 4 84 ...

%C 9 -14 20 -24 32 -32 48 -32 80 0 ...

%C -23 34 -44 56 -64 80 -80 112 -80 176 ...

%C 57 -78 100 -120 144 -160 192 -192 256 -192 ...

%C ... .

%C The signature is valid for every row.

%C a(n-2) + a(n-1) = A001045(n).

%C a(n-2) + a(n+1) = A062510(n) = 3*A001045(n).

%C a(n-2) + a(n+3) = see A144472(n+1).

%C Second subdiagonal: 1, 6, 20, 56, 144, 352, ... = A014480(n).

%C First subdiagonal: -A036895(n) = -2*A001787(n).

%C Main diagonal: A001787(n) = -first and -third upper diagonals.

%C Second, fourth and fifth upper diagonals: A001792(n), A045891(n+2) and A172160(n+1). (End)

%H Stanislav Sykora, <a href="/A053088/b053088.txt">Table of n, a(n) for n = 0..1000</a>

%H Paul Barry, <a href="https://cs.uwaterloo.ca/journals/JIS/VOL19/Barry/barry321.html">Jacobsthal Decompositions of Pascal's Triangle, Ternary Trees, and Alternating Sign Matrices</a>, Journal of Integer Sequences, 19, 2016, #16.3.5.

%H Iwan Duursma, Xiao Li, and Hsin-Po Wang, <a href="https://arxiv.org/abs/2006.08911">Multilinear Algebra for Distributed Storage</a>, arXiv:2006.08911 [cs.IT], 2020.

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (0,3,2).

%F G.f.: 1 / (1-3*x^2-2*x^3).

%F With offset 1: a(1)=1; a(n) = 2*a(n-1) - (-1)^n*n; a(n) = (1/9)*(2^(n+1) - (-1)^n*(3*n+2)). - _Benoit Cloitre_, Nov 02 2002

%F a(n) = Sum_{k=0..floor(n/2)} A078008(n-2k). - _Paul Barry_, Nov 24 2003

%F a(n) = Sum_{k=0..floor(n/2)} binomial(k, n-2k)*3^k*(2/3)^(n-2k). - _Paul Barry_, Oct 16 2004

%F a(n) = Sum_{k=0..n} A078008(k)*(1 - (-1)^(n+k-1))/2. - _Paul Barry_, Apr 16 2005

%F a(n) = ( 2^(n+2) + (-1)^n*(3*n+5) )/9 (see also the B. Cloitre comment above). From the o.g.f. 1/(1-3*x^2-2*x^3) = 1/((1-2*x)*(1+x)^2) = (3/(1+x)^2 + 2/(1+x) + 4/(1-2*x))/9. - _Wolfdieter Lang_, Jun 25 2010

%F From _Wolfdieter Lang_, Aug 26 2010: (Start)

%F a(n) = a(n-1) + 2*a(n-2) + (-1)^n for n > 1, a(0)=1, a(1)=0.

%F Due to the identity for the o.g.f. A(x): A(x) = x*(1+2*x)*A(x) + 1/(1+x).

%F (This recurrence was observed by _Gary Detlefs_ in a 08/25/10 e-mail to the author.) (End)

%F G.f.: Sum_{n>=0} binomial(3*n,n)*x^n / (1+x)^(3*n+3). - _Paul D. Hanna_, Mar 03 2012

%F E.g.f.: 1 + (1/9)*(exp(-x)*(3*x - 2) + 2*exp(2*x)). - _Stefano Spezia_, Sep 27 2019

%t CoefficientList[Series[1/(1 - 3 x^2 - 2 x^3), {x, 0, 32}], x] (* _Michael De Vlieger_, Sep 30 2019 *)

%o (PARI) c(n)=(2^(n+1)-(-1)^n*(3*n+2))/9; a(n)=c(n+1); \\ _Stanislav Sykora_, Nov 27 2013

%Y Cf. A232603, A232604.

%Y Cf. A001045, A001787, A001792, A014480, A036895, A062510, A045891, A172160.

%K nonn,easy

%O 0,3

%A Pauline Gorman (pauline(AT)gorman65.freeserve.co.uk), Feb 26 2000

%E More terms from _James A. Sellers_, Feb 28 2000 and _Christian G. Bower_, Feb 29 2000

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Last modified April 19 15:34 EDT 2024. Contains 371794 sequences. (Running on oeis4.)