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A052495
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Take n-th prime p, let P = all primes having same digits; a(n) = q-p where q is smallest prime in P >p if q exists; otherwise a(n) = p-r where r is largest prime in P <p if r exists; otherwise a(n) = 0.
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5
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0, 0, 0, 0, 0, 18, 54, 0, 0, 0, 18, 36, 0, 0, 0, 0, 0, 0, 0, 54, 36, 18, 0, 0, 18, 0, 0, 594, 0, 18, 144, 180, 36, 54, 270, 0, 414, 450, 450, 144, 18, 630, 720, 54, 522, 720, 0, 0, 0, 0, 0, 54, 180, 270, 0, 0, 0, 144, 450, 540, 540, 54, 0, 180, 18, 144, 18, 36, 396, 90, 0, 234
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OFFSET
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1,6
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COMMENTS
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The primes in P are required to have the same number of digits as p; thus internal 0's must remain internal 0's.
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LINKS
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EXAMPLE
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a(41)=18 because the 41st prime is 179. The primes having these digits are 179, 197, 719 and 971. The distance from 179 to 197 = 18.
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CROSSREFS
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KEYWORD
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base,easy,nonn
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AUTHOR
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STATUS
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approved
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