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A051836
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a(n) = n*(n+1)*(n+2)*(n+3)*(3*n+2)/120.
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15
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0, 1, 8, 33, 98, 238, 504, 966, 1716, 2871, 4576, 7007, 10374, 14924, 20944, 28764, 38760, 51357, 67032, 86317, 109802, 138138, 172040, 212290, 259740, 315315, 380016, 454923, 541198, 640088, 752928, 881144, 1026256, 1189881, 1373736, 1579641, 1809522, 2065414
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OFFSET
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0,3
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COMMENTS
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5-dimensional version of pentagonal-based pyramidal numbers. - Ben Creech (mathroxmysox(AT)yahoo.com)
If Y is a 3-subset of an n-set X then, for n>=7, a(n-6) is the number of 7-subsets of X having at least two elements in common with Y. - Milan Janjic, Nov 23 2007
a(n) is also the number of odd chordless cycles in the graph complement of the (n+1)-Andrásfai graph. - Eric W. Weisstein, Apr 14 2017
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REFERENCES
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Albert H. Beiler, Recreations in the Theory of Numbers, Dover, N.Y., 1964, pp. 194-196.
Herbert John Ryser, Combinatorial Mathematics, "The Carus Mathematical Monographs", No. 14, John Wiley and Sons, 1963, pp. 1-8.
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LINKS
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FORMULA
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a(n) = C(n+4, n)*(3n+5)/5.
Sum_{n>=1} 1/a(n) = 135*sqrt(3)*Pi/14 - 1215*log(3)/14 + 925/21.
Sum_{n>=1} (-1)^(n+1)/a(n) = 135*sqrt(3)*Pi/7 - 880*log(2)/7 - 355/21. (End)
E.g.f.: (1/5!)*x*(120 + 360*x + 240*x^2 + 50*x^3 + 3*x^4)*exp(x). - G. C. Greubel, Dec 27 2023
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EXAMPLE
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By the fourth comment: A000217(1..6) and A000326(1..6) give the term a(6) = 1*21+5*15+12*10+22*6+35*3+51*1 = 504. - Bruno Berselli, Jun 27 2013
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MAPLE
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with (combinat):a[0]:=0:for n from 1 to 50 do a[n]:=stirling2(n+2, n)+a[n-1] od: seq(a[n], n=0..34); # Zerinvary Lajos, Mar 17 2008
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MATHEMATICA
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CoefficientList[Series[x (1 + 2 x) / (1 - x)^6, {x, 0, 33}], x] (* Vincenzo Librandi, Jul 04 2017 *)
LinearRecurrence[{6, -15, 20, -15, 6, -1}, {0, 1, 8, 33, 98, 238}, 40] (* Harvey P. Dale, Jun 01 2018 *)
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PROG
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(Magma) [0] cat [Binomial(n+4, n)*(3*n+5)/5: n in [0..40]]; // Vincenzo Librandi, Jul 04 2017
(SageMath) [((3*n+2)/(n+4))*binomial(n+4, 5) for n in range(41)] # G. C. Greubel, Dec 27 2023
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CROSSREFS
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Cf. A093560 ((3, 1) Pascal, column m=5).
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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Simpler definition from Ben Creech (mathroxmysox(AT)yahoo.com), Nov 13 2005
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STATUS
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approved
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