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A051674
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Prime(n)^prime(n).
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62
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4, 27, 3125, 823543, 285311670611, 302875106592253, 827240261886336764177, 1978419655660313589123979, 20880467999847912034355032910567, 2567686153161211134561828214731016126483469
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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COMMENTS
| n such that bigomega(n)^(bigomega(n))=n, where bigomega=A001222. - Lekraj Beedassy, Aug 21 2004
Positive n such that n' = n, where n' is the arithmetic derivative of n. - T. D. Noe (noe(AT)sspectra.com), Oct 12 2004
David Beckwith proposes (in the AMM reference): "Let n be a positive integer and let p be a prime number. Prove that (p^p) | n! implies that (p^(p+1)) | n!" - Jonathan Vos Post, Feb 20 2006
Subsequence of A100716; A003415(m*a(n))=A129283(m)*a(n), especially A003415(a(n))=a(n). - Reinhard Zumkeller, Apr 07 2007
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REFERENCES
| David Beckwith, Problem 11158, American Mathematical Monthly, Vol. 112, No. 5 (May 2005), p. 468.
J.-M. De Koninck & A. Mercier, 1001 Problemes en Theorie Classique Des Nombres, Problem 740 pp. 95; 312, Ellipses Paris 2004.
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LINKS
| T. D. Noe, Table of n, a(n) for n=1..40
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EXAMPLE
| a(3) = 5^5 = 3125.
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MATHEMATICA
| Array[Prime[ # ]^Prime[ # ] &, 12] [Vladimir Orlovsky, May 01 2008]
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PROG
| (Haskell)
a051674_list = map (\p -> p ^ p) a000040_list
-- Reinhard Zumkeller, Jan 21 2012
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CROSSREFS
| Cf. A000040.
Cf. A003415 (arithmetic derivative of n).
Cf. A129150, A129151, A129152.
Cf. A048102, A072873 (multipliative closure).
Sequence in context: A133032 A110763 A066352 * A132641 A008973 A132646
Adjacent sequences: A051671 A051672 A051673 * A051675 A051676 A051677
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KEYWORD
| nonn
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AUTHOR
| Asher Auel (asher.auel(AT)reed.edu)
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