|
| |
|
|
A051674
|
|
Prime(n)^prime(n).
|
|
70
|
|
|
|
4, 27, 3125, 823543, 285311670611, 302875106592253, 827240261886336764177, 1978419655660313589123979, 20880467999847912034355032910567, 2567686153161211134561828214731016126483469
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
|
OFFSET
|
1,1
|
|
|
COMMENTS
|
n such that bigomega(n)^(bigomega(n))=n, where bigomega=A001222. - Lekraj Beedassy, Aug 21 2004
Positive n such that n' = n, where n' is the arithmetic derivative of n. - T. D. Noe, Oct 12 2004
David Beckwith proposes (in the AMM reference): "Let n be a positive integer and let p be a prime number. Prove that (p^p) | n! implies that (p^(p + 1)) | n!" - Jonathan Vos Post, Feb 20 2006
Subsequence of A100716; A003415(m*a(n))=A129283(m)*a(n), especially A003415(a(n))=a(n). - Reinhard Zumkeller, Apr 07 2007
|
|
|
REFERENCES
|
David Beckwith, Problem 11158, American Mathematical Monthly, Vol. 112, No. 5 (May 2005), p. 468.
J.-M. De Koninck & A. Mercier, 1001 Problemes en Theorie Classique Des Nombres, Problem 740 pp. 95; 312, Ellipses Paris 2004.
|
|
|
LINKS
|
T. D. Noe, Table of n, a(n) for n = 1..40
|
|
|
EXAMPLE
|
a(1) = 2^2 = 4.
a(2) = 3^3 = 27.
a(3) = 5^5 = 3125.
|
|
|
MATHEMATICA
|
Array[Prime[ # ]^Prime[ # ] &, 12] (* Vladimir Orlovsky, May 01 2008 *)
|
|
|
PROG
|
(Haskell)
a051674_list = map (\p -> p ^ p) a000040_list
-- Reinhard Zumkeller, Jan 21 2012
(PARI) a(n)=n=prime(n); n^n \\ Charles R Greathouse IV, Mar 20 2013
|
|
|
CROSSREFS
|
Cf. A000040, A003415 (arithmetic derivative of n), A129150, A129151, A129152, A048102, A072873 (multiplicative closure), A104126.
Sequence in context: A133032 A110763 A066352 * A132641 A008973 A132646
Adjacent sequences: A051671 A051672 A051673 * A051675 A051676 A051677
|
|
|
KEYWORD
|
nonn,easy
|
|
|
AUTHOR
|
Asher Auel (asher.auel(AT)reed.edu)
|
|
|
STATUS
|
approved
|
| |
|
|