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a(n+1) = a(n) + sum of digits of a(n)^2.
0

%I #4 Nov 13 2010 13:18:02

%S 197,225,243,270,288,315,342,369,387,423,459,477,504,522,549,558,576,

%T 603,630,657,684,720,738,765,792,819,846,873,900,909,936,972,1008,

%U 1026,1053,1080,1098,1116,1143,1170,1197,1224,1260,1287,1323,1350,1368,1395

%N a(n+1) = a(n) + sum of digits of a(n)^2.

%Y Cf. A033298.

%K nonn,base,easy,less

%O 1,1

%A Miklos SZABO (mike(AT)ludens.elte.hu)