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Every 25th Fibocyclotomic number divided by 5.
1

%I #3 May 01 2014 02:49:07

%S 1487,1241,18635111,20301765,70845391935385247435,22295845,

%T 975045119839962277471200,4683036088407831,1070886168667259594766160,

%U 70844547341354026205,51054721551471747728658198373574250149039

%N Every 25th Fibocyclotomic number divided by 5.

%F a(n) = A051258(n)/5

%Y Cf. A051258, A051259.

%K nonn

%O 1,1

%A _Antti Karttunen_, Oct 24 1999