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Every 25th Fibocyclotomic number.
1

%I #3 May 01 2014 02:49:07

%S 7435,6205,93175555,101508825,354226959676926237175,111479225,

%T 4875225599199811387356000,23415180442039155,

%U 5354430843336297973830800,354222736706770131025,255273607757358738643290991867871250745195

%N Every 25th Fibocyclotomic number.

%C All divisible by fib(5) = 5.

%F a(n) = A051258(25n)

%Y Cf. A051258.

%K nonn

%O 1,1

%A _Antti Karttunen_, Oct 24 1999