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a(n) = (2^5^(n+1) - 1)/(2^5^n - 1).
3

%I #16 Dec 24 2022 04:53:43

%S 31,1082401,1267650638007162390353805312001,

%T 3273390607896141870013189696827599152293599089395397756694773868291726792119530172040230983402733964346814858022765439290901496446006940490331586560001

%N a(n) = (2^5^(n+1) - 1)/(2^5^n - 1).

%t Table[(2^5^(n+1) - 1)/(2^5^n - 1),{n,0,3}] (* _Stefano Spezia_, Dec 23 2022 *)

%Y Cf. A051154, A051156, A051157.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_