



0, 1, 2, 2, 3, 4, 4, 5, 6, 7, 8, 9, 9, 10, 11, 11, 12, 13, 14, 15, 16, 16, 17, 18, 18, 19, 20, 20, 21, 22, 22, 23, 24, 24, 25, 26, 27, 28, 29, 29, 30, 31, 31, 32, 33, 34, 35, 36, 36, 37, 38, 38, 39, 40, 40, 41, 42, 42, 43, 44, 44, 45, 46, 47, 48, 49, 49
(list;
graph;
refs;
listen;
history;
text;
internal format)



OFFSET

0,3


COMMENTS

Duplicate of A050294? [Joerg Arndt, Apr 27 2013]
From Michel Dekking, Feb 10 2019: (Start)
The answer to Joerg Arndt's question is: yes (modulo an offset). To see this, it suffices to prove that the two sequences of first differences Da and Db of a= A051068 and b:=A050294 are equal. Clearly the sequence Da of first differences of a is the sequence A014578. According to Philippe Deleham (2004), Da equals 0x = 0110110111110..., where x is the fixed point of the morphism 0>111, 1>110.
From Vladimir Shevelev (2011) we know a formula for b=A050294: b(n) = nb(floor(n/3)). This gives that the sequence of first differences Db:=(b(n+1)b(n)) of b satisfies
Db(3m+1) = Db(3m+2) = 1, and Db(3m+3) = 1  Db(m).
This implies that Db = x, the fixed point of 0>111, 1>110.
(End)


LINKS

Table of n, a(n) for n=0..66.


FORMULA

a(3^n) = A015518(n+1) = (1)^n*A014983(n+1).  Philippe Deléham, Mar 31 2004


CROSSREFS

Cf. A014578, A051069, A050294.
Sequence in context: A127038 A175268 A241948 * A050294 A349775 A097950
Adjacent sequences: A051065 A051066 A051067 * A051069 A051070 A051071


KEYWORD

nonn


AUTHOR

N. J. A. Sloane, Gary W. Adamson


STATUS

approved



