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%I #36 Sep 03 2013 04:00:30
%S 7,359905,5154625,5886265,2264566322,7288270322,7769878442,
%T 13180385785,189700037905,196092541922,466029676802,524476614025,
%U 593410971265,753942150745,760761410042,1891149384842,3432016687082,4485159043225,5563116250945,6003635279425
%N Start of consecutive solutions of phi(x) = phi(x+2). That is, phi(a(n)) = phi(a(n)+2) and phi(a(n)+1) = phi(a(n)+3).
%C a(11) <= 524476614025. - _Donovan Johnson_, Feb 04 2011
%C No other terms < 9.585 x 10^12 [ _Jud McCranie_, Sep 03 2013]
%e phi(7) = phi(9) = 6 and phi(8) = phi(10) = 4, so 7 is in the sequence.
%Y Cf. A000010.
%K nonn
%O 1,1
%A _Jud McCranie_, Jan 01 2000
%E a(6)-a(10) from _Donovan Johnson_, Feb 04 2011
%E a(11)-a(15) from _Jud McCranie_, Jan 02 2013
%E a(16)-a(20) from _Jud McCranie_, Aug-Sep 2013
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