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 A048716 Numbers n such that binary expansion matches ((0)*00(1?)1)*(0*). 13
 0, 1, 2, 3, 4, 6, 8, 9, 12, 16, 17, 18, 19, 24, 25, 32, 33, 34, 35, 36, 38, 48, 49, 50, 51, 64, 65, 66, 67, 68, 70, 72, 73, 76, 96, 97, 98, 99, 100, 102, 128, 129, 130, 131, 132, 134, 136, 137, 140, 144, 145, 146, 147, 152, 153, 192, 193, 194, 195, 196, 198, 200, 201 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,3 COMMENTS If bit i is 1, then bits i+-2 must be 0. All terms satisfy A048725(n) = 5*n. It appears that n is in the sequence if and only if C(5n,n) is odd (cf. A003714). - Benoit Cloitre, Mar 09 2003 Yes, as remarked in A048715, "This is easily proved using the well-known result that the multiplicity with which a prime p divides C(n+m,n) is the number of carries when adding n+m in base p." - Jason Kimberley, Dec 21 2011 A116361(a(n)) <= 2. - Reinhard Zumkeller, Feb 04 2006 LINKS Charles R Greathouse IV, Table of n, a(n) for n = 1..10000 MATHEMATICA Reap[Do[If[OddQ[Binomial[5n, n]], Sow[n]], {n, 0, 400}]][[2, 1]] (* Second program: *) filterQ[n_] := With[{bb = IntegerDigits[n, 2]}, MatchQ[bb, {0}|{1}|{1, 1}|{___, 0, _, 1, ___}|{___ 1, _, 0, ___}] && !MatchQ[bb, {___, 1, _, 1, ___}]]; Select[Range[0, 201], filterQ] (* Jean-François Alcover, Dec 31 2020 *) PROG (PARI) is(n)=!bitand(n, n>>2) \\ Charles R Greathouse IV, Oct 03 2016 (PARI) list(lim)=my(v=List(), n, t); while(n<=lim, t=bitand(n, n>>2); if(t, n+=1<

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Last modified October 6 21:32 EDT 2022. Contains 357270 sequences. (Running on oeis4.)