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%I #12 May 16 2018 10:14:45
%S 0,1,1,2,2,3,2,4,4,5,4,6,5,6,5,7,6,8,6,8,8,8,6,9,9,9,10,11,10,11,9,12,
%T 12,12,11,14,13,13,11,14,12,14,12,13,14,15,12,15,15,15,14,16,14,17,15,
%U 17,17,16,14,17,15,16,14,19,18,20,18,18,18,20,17,20,19,19,19,20,19,21
%N a(n) is the maximal value of Omega(binomial(n,k)) over k, where Omega = A001222.
%e n=24: the values of Omega(binomial(24,k)) as k runs from 0 to 24 are {0, 4, 4, 5, 5, 7, 6, 8, 6, 8, 8, 9, 7, 9, 8, 8, 6, 8, 6, 7, 5, 5, 4, 4, 0}. The maximum is 9, so a(24)=9.
%o (PARI) a(n) = vecmax(vector(n+1, k, bigomega(binomial(n, k-1)))); \\ _Michel Marcus_, May 14 2018
%Y Cf. A001222, A001221, A046660, A048273, A048275.
%K nonn
%O 1,4
%A _Labos Elemer_
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