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A048440
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Take the first n numbers written in base 8, concatenate them, then convert from base 8 to base 10.
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17
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1, 10, 83, 668, 5349, 42798, 342391, 21913032, 1402434057, 89755779658, 5744369898123, 367639673479884, 23528939102712589, 1505852102573605710, 96374534564710765455, 6167970212141488989136, 394750093577055295304721
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OFFSET
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1,2
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COMMENTS
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83 is the only prime in this sequence among the first 3000 terms (email from Kurt Foster, Oct 24 2015). - N. J. A. Sloane, Oct 25 2015
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LINKS
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EXAMPLE
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a(9): (1)(2)(3)(4)(5)(6)(7)(10)(11) = 12345671011_8 = 1402434057.
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MATHEMATICA
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If[STARTPOINT==1, n={}, n=Flatten[IntegerDigits[Range[STARTPOINT-1], 8]]]; Table[AppendTo[n, IntegerDigits[w, 8]]; n=Flatten[n]; FromDigits[n, 8], {w, STARTPOINT, ENDPOINT}] (* Dylan Hamilton, Aug 11 2010 *)
Table[FromDigits[Flatten[IntegerDigits[#, 8]&/@Range[n]], 8], {n, 20}] (* Harvey P. Dale, Dec 07 2012 *)
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PROG
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(Magma) [n eq 1 select 1 else Self(n-1)*8^(1+Ilog(8, n))+n: n in [1..20]]; // Vincenzo Librandi, Dec 30 2012
(Python)
from functools import reduce
def A048440(n): return reduce(lambda i, j:(i<<3*(1+(j.bit_length()-1)//3))+j, range(n+1)) # Chai Wah Wu, Feb 26 2023
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CROSSREFS
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Concatenation of first n numbers in other bases: 2: A047778, 3: A048435, 4: A048436, 5: A048437, 6: A048438, 7: A048439, 8: this sequence, 9: A048441, 10: A007908, 11: A048442, 12: A048443, 13: A048444, 14: A048445, 15: A048446, 16: A048447.
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KEYWORD
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nonn,base,easy
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AUTHOR
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STATUS
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approved
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