

A047975


Let (p1,p2), (p3,p4) be two pairs of successive primes such that p1*p2=p3+p41, p2p1=p4p3; sequence gives p2p1=p4p3.


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2, 4, 2, 4, 6, 6, 4, 2, 4, 4, 2, 6, 4, 6, 4, 4, 6, 4, 2, 2, 4, 2, 4, 6, 6, 10, 8, 4, 4, 4, 2, 4, 4, 2, 6, 6, 4, 2, 8, 6, 12, 2, 2, 8, 10, 2, 12, 6, 4, 4, 14, 2, 18, 16, 6, 10, 4, 8, 4, 2, 8, 12, 2, 8, 12, 10, 6, 2, 6
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