OFFSET
1,2
COMMENTS
a(16) > 10^13. a(16) must have at least 5 prime factors (counted with multiplicity) because one of the 16 consecutive numbers is divisible by 2^4. - Donovan Johnson, Apr 01 2013
EXAMPLE
a(4) = 602 as 602 = 2 * 7 * 43, 603 = 3 * 3 * 67, 604 = 2 * 2 * 151, 605 = 5 * 11 * 11 so four consecutive positive integers have the same number of prime factors starting at 602, the first such number. - David A. Corneth, Feb 24 2024
CROSSREFS
KEYWORD
nonn,more
AUTHOR
EXTENSIONS
More terms from Vladeta Jovovic, Aug 06 2002
More terms from Martin Fuller, Nov 21 2006
STATUS
approved