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EXAMPLE
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For n=3 the 20 different arrangements of -1,-1,-1,1,1,1 result in 7 energy levels (sum of signed inverse distances):
{0,0,0,1,1,1},{1,1,1,0,0,0}: 13/10
{0,0,1,0,1,1},{1,1,0,1,0,0}: -41/30
{0,0,1,1,0,1},{0,1,0,0,1,1},{1,0,1,1,0,0},{1,1,0,0,1,0}: -56/30
{0,0,1,1,1,0},{0,1,1,1,0,0},{1,0,0,0,1,1},{1,1,0,0,0,1}: -8/10
{0,1,0,1,0,1},{1,0,1,0,1,0}: -37/10
{0,1,0,1,1,0},{0,1,1,0,1,0},{1,0,0,1,0,1},{1,0,1,0,0,1}: -89/30
{0,1,1,0,0,1},{1,0,0,1,1,0}: -71/30
so the multiplicities are 4*2 + 3*4 = 20 = binomial(6,3).
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