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A045572 Numbers that are odd but not divisible by 5. 40
1, 3, 7, 9, 11, 13, 17, 19, 21, 23, 27, 29, 31, 33, 37, 39, 41, 43, 47, 49, 51, 53, 57, 59, 61, 63, 67, 69, 71, 73, 77, 79, 81, 83, 87, 89, 91, 93, 97, 99, 101, 103, 107, 109, 111, 113, 117, 119, 121, 123, 127, 129, 131, 133, 137, 139, 141, 143, 147, 149, 151, 153 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,2

COMMENTS

Contains the repunits R_n, (A000042 or A002275): For any m in the sequence (divisible by neither 2 nor 5), Euler's theorem (i.e. m|10^m-1=9*R_n) guarantees that R_n is always some multiple of m (see A099679) and thus forms a subsequence. - Lekraj Beedassy, Oct 26 2004

Inverse formula: n = 4*floor(a(n)/10) + floor([a(n) mod 10]/3) + 1 - Carl R. White, Feb 06 2008

Numbers ending with 1, 3, 7 or 9. [From Lekraj Beedassy , Apr 04 2009]

A000035(a(n))*(1-A079998(a(n)))=1; complement of A065502. [From Reinhard Zumkeller, Nov 15 2009]

Union of evenish and oddish numbers, cf. A045797, A045798. [Reinhard Zumkeller, Dec 10 2011]

Numbers k such that k^(4*j) mod 10 = 1, for any j. [From Gary Detlefs, Jan 03 2012]

LINKS

Vincenzo Librandi, Table of n, a(n) for n = 1..10000

Index to sequences with linear recurrences with constant coefficients, signature (1,0,0,1,-1).

FORMULA

a(n)=-1+Sum_{k=0..n}{(1/12)*{5*(k mod 4)+11*[(k+1) mod 4]-[(k+2) mod 4]+5*[(k+3) mod 4]}} - Paolo P. Lava, Dec 20 2007

a(n) = 10*floor((n-1)/4) + 2*floor( (4*[(n-1) mod 4]+1)/3 ) + 1 a(n) = a(n-1) + 2 + 2*floor([(x+6) mod 10]/9) - Carl R. White , Feb 06 2008

a(n) = 2*n + 2*floor((n-3)/4) + 1 - Kenneth Hammond (weregoose(AT)gmail.com), Mar 07 2008

a(n) = -1 + 2*n + 2*floor((n+1)/4) - Kenneth Hammond (weregoose(AT)gmail.com), Mar 25 2008

a(n)= a(n-1) +a(n-4) -a(n-5). G.f.: x*(1+2*x+4*x^2+2*x^3+x^4)/ ((1+x) * (x^2+1) * (x-1)^2). - R. J. Mathar, Sep 22 2009

a(n) = (10*n+2*(-1)^(n*(n+1)/2)-(-1)^n-5)/4. - Bruno Berselli, Nov 06 2011

EXAMPLE

a(18) = 10*floor(17/4) + 2*floor( (4*[17 mod 4]+1)/3 ) + 1

= 10*4 + 2*floor( (4*[1]+1)/3 ) + 1

= 40 + 2*floor(5/3) + 1

= 40 + 2*1 + 1

= 43

MATHEMATICA

Flatten[Table[10n + {1, 3, 7, 9}, {n, 0, 19}]] (* Alonso del Arte, Jan 13 2012 *)

PROG

(GNU bc) scale=0; for(n=1; n<=100; n++) 10*((n-1)/4)+2*((4*((n-1)%4)+1)/3)+1 /* Carl R. White, Feb 06 2008 */

(PARI) a(n)=10*(n>>2)+[-1, 1, 3, 7][n%4+1] \\ Charles R Greathouse IV, Jul 31 2011

(MAGMA) [ 2*n + 2*Floor((n-3)/4) + 1: n in [1..70] ]; // Vincenzo Librandi, Aug 01 2011

(Haskell)

a045572 n = a045572_list !! (n-1)

a045572_list = filter ((/= 0) . (`mod` 5)) a005408_list

-- Reinhard Zumkeller, Dec 10 2011

CROSSREFS

See also A085820, A082768 (Numbers that begin with 1, 3, 7 or 9).

Cf. A005408.

Sequence in context: A165631 A005818 A085820 * A069254 A105585 A080903

Adjacent sequences:  A045569 A045570 A045571 * A045573 A045574 A045575

KEYWORD

easy,nonn,changed

AUTHOR

Jeff Burch

STATUS

approved

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Last modified May 26 02:03 EDT 2013. Contains 225652 sequences.