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A044881
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Numbers having, in base 10, (sum of even run lengths)=(sum of odd run lengths).
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3
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1001, 1002, 1003, 1004, 1005, 1006, 1007, 1008, 1009, 1011, 1022, 1033, 1044, 1055, 1066, 1077, 1088, 1099, 1101, 1102, 1103, 1104, 1105, 1106, 1107, 1108, 1109, 1120, 1121, 1123, 1124, 1125, 1126, 1127, 1128, 1129
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listen;
history;
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internal format)
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OFFSET
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1,1
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LINKS
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PROG
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(Python)
from itertools import groupby
def ok(n):
rl_sums = [0, 0]
for k, g in groupby(str(n)):
rl = len(list(g))
rl_sums[rl%2] += rl
return rl_sums[0] == rl_sums[1]
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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