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%I #13 Sep 05 2020 20:29:26
%S 0,2,2,1,2,0,1,0,3,0,4,1,1,0,1,1,0,1,0,1,0,1,0,0,1,0,1,1,0,0,0,1,0,1,
%T 1,0,0,1,0,1,0,1,1,1,0,0,1,1,1,0,0,0,1,0,0,0,0,1,0,0,0,1,0,2,0,0,1,0,
%U 0,0,0,2,0,1,0,0,1,0,1,0,0,0,1,1,0,1,0,0
%N Let L(n) = n-th lucky number. Then a(1)=0; a(n) is largest number m such that all divisors of L(n)^m are lucky numbers.
%e To get a(3) we compute L(3)=7, divisors of 7^2 are 1, 7, 49. They are lucky numbers but 7^3 is not, so a(3)=2.
%Y Cf. A000959.
%K nonn
%O 1,2
%A _Naohiro Nomoto_, Oct 08 2000
%E More terms from _Sascha Kurz_, Oct 14 2001
%E Offset changed to 1 and more terms from _Jinyuan Wang_, Sep 05 2020
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