OFFSET
1,1
PROG
(Python)
from itertools import groupby
def ok(n): return len(list(g for k, g in groupby(hex(n)[2:])))%2 == 0
print(list(filter(ok, range(1, 80)))) # Michael S. Branicky, Jun 18 2021
CROSSREFS
KEYWORD
nonn,base
AUTHOR
STATUS
approved