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A042964 Numbers congruent to 2 or 3 mod 4. 18
2, 3, 6, 7, 10, 11, 14, 15, 18, 19, 22, 23, 26, 27, 30, 31, 34, 35, 38, 39, 42, 43, 46, 47, 50, 51, 54, 55, 58, 59, 62, 63, 66, 67, 70, 71, 74, 75, 78, 79, 82, 83, 86, 87, 90, 91, 94, 95, 98, 99, 102, 103, 106, 107, 110, 111, 114, 115, 118, 119, 122, 123, 126, 127 (list; graph; refs; listen; history; internal format)
OFFSET

1,1

COMMENTS

Also numbers m such that binomial(m+2,m) mod 2 = 0. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Oct 20 2007

Also numbers m such that floor(1+(m/2)) mod 2 = 0. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Oct 20 2007

Partial sums of the sequence 2,1,3,1,3,1,3,1,3,1, ... which has period 2. - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Oct 20 2007

In groups of four add and divide by two the odd and even numbers - George E. Antoniou (george.antoniou(AT)montclair.edu), Dec 12 2001.

Comments from Jeremy Gardiner (jeremy.gardiner(AT)btinternet.com) on the "mystery calculator". There are 6 cards.

Card 0 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, ... (A005408 sequence)

Card 1 2, 3, 6, 7, 10, 11, 14, 15, 18, 19, 22, 23, 26, 27, 30, 31, 34, 35, 38, 39, ... (this sequence)

Card 2 4, 5, 6, 7, 12, 13, 14, 15, 20, 21, 22, 23, 28, 29, 30, 31, 36, 37, 38, 39, ... ( A047566)

Card 3 8, 9, 10, 11, 12, 13, 14, 15, 24, 25, 26, 27, 28, 29, 30, 31, 40, 41, 42, ... (A115419)

Card 4 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 48, 49, 50, ... (A115420)

Card 5 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, ... (A115421)

The trick: You secretly select a number between 1 and 63 from one of the cards. You indicate to me the cards on which that number appears; I tell you the number you selected!

The solution: I add together the first term from each of the indicated cards. The total equals the selected number. The numbers in each sequence all have a "1" in the same position in their binary expansion. Example: You indicate cards 1, 3 and 5. Your selected number is 2+8+32 = 42.

Numbers having a 1 in position 1 of their binary expansion. One of the mystery calculator sequences: A005408, A042964, A047566, A115419, A115420, A115421. - Jeremy Gardiner (jeremy.gardiner(AT)btinternet.com), Jan 22 2006

A133872(a(n)) = 0; complement of A042948. [From Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Oct 03 2008]

Also the 2nd Witt transform of A040000 [Moree]. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Nov 08 2008]

LINKS

Maths Magic, Mystery Calculator.

Pieter Moree, The formal series Witt transform, Discr. Math. no. 295 vol. 1-3 (2005) 143-160. [From R. J. Mathar, Nov 08 2008]

FORMULA

G.f.: (2+x+x^2)/((1-x)*(1-x^2)). a(n)=a(n-1)+2+(-1)^n - Michael Somos, Jan 12 2000.

a(n) = 2n if n is odd else n = 2n-1. - Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Oct 16 2003

a(n) = [2+(-1)^n+(-1)^(n+1)]*n-[1+(-1)^n]/2, n>=1 - Paolo P. Lava (paoloplava(AT)gmail.com), Feb 15 2008

a(n) = (3+(-1)^(n-1))/2 + 2*(n-1) = 2n+2-(n mod 2). - Hieronymus Fischer (Hieronymus.Fischer(AT)gmx.de), Oct 20 2007

a(n) = 4*n-a(n-1)-3 (with a(1)=2) [From Vincenzo Librandi, Nov 17 2010].

PROG

(PARI) a(n)=2*n+2-n%2

CROSSREFS

a(n) = A047406(n)/2.

Cf. A000040, A133620, A133621, A133622, A133630, A133635.

Cf. A133872, A133882, A133890, A133900, A133910.

Sequence in context: A188084 A107998 A053438 * A062837 A190670 A073170

Adjacent sequences:  A042961 A042962 A042963 * A042965 A042966 A042967

KEYWORD

nonn

AUTHOR

N. J. A. Sloane (njas(AT)research.att.com).

EXTENSIONS

Edited by N. J. A. Sloane (njas(AT)research.att.com), Jun 30 2008 at the suggestion of R. J. Mathar

Corrected by Jaroslav Krizek (jaroslav.krizek(AT)atlas.cz), Dec 18 2009

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Last modified February 16 07:10 EST 2012. Contains 205874 sequences.