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Continued fraction for sqrt(863).
1

%I #12 Mar 10 2017 16:44:55

%S 29,2,1,1,1,7,1,3,3,5,29,5,3,3,1,7,1,1,1,2,58,2,1,1,1,7,1,3,3,5,29,5,

%T 3,3,1,7,1,1,1,2,58,2,1,1,1,7,1,3,3,5,29,5,3,3,1,7,1,1,1,2,58,2,1,1,1,

%U 7,1,3,3,5,29,5,3,3,1,7,1,1,1,2,58,2,1,1,1,7,1,3,3,5

%N Continued fraction for sqrt(863).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_20">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(863)),confrac);

%t ContinuedFraction[Sqrt[863], 100] (* _Wesley Ivan Hurt_, Nov 20 2013 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.