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Continued fraction for sqrt(862).
1

%I #11 Jun 16 2024 19:52:17

%S 29,2,1,3,1,1,9,4,2,2,2,1,5,1,4,2,19,8,2,1,28,1,2,8,19,2,4,1,5,1,2,2,

%T 2,4,9,1,1,3,1,2,58,2,1,3,1,1,9,4,2,2,2,1,5,1,4,2,19,8,2,1,28,1,2,8,

%U 19,2,4,1,5,1,2,2,2,4,9,1,1,3,1,2,58,2,1,3,1,1,9,4,2

%N Continued fraction for sqrt(862).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_40">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(862)),confrac);

%t ContinuedFraction[Sqrt[862],100] (* _Harvey P. Dale_, Jun 16 2024 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.