%I #17 Dec 26 2023 08:06:07
%S 28,1,2,1,1,1,1,4,1,1,1,1,2,1,56,1,2,1,1,1,1,4,1,1,1,1,2,1,56,1,2,1,1,
%T 1,1,4,1,1,1,1,2,1,56,1,2,1,1,1,1,4,1,1,1,1,2,1,56,1,2,1,1,1,1,4,1,1,
%U 1,1,2,1,56,1,2,1,1,1,1,4,1,1,1,1,2,1,56,1,2,1,1,1
%N Continued fraction for sqrt(825).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_14">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,0,0,0,0,0,0,1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(825)),confrac);
%t ContinuedFraction[Sqrt[825],100] (* _Harvey P. Dale_, Sep 28 2012 *)
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_.