login
Continued fraction for sqrt(825).
2

%I #17 Dec 26 2023 08:06:07

%S 28,1,2,1,1,1,1,4,1,1,1,1,2,1,56,1,2,1,1,1,1,4,1,1,1,1,2,1,56,1,2,1,1,

%T 1,1,4,1,1,1,1,2,1,56,1,2,1,1,1,1,4,1,1,1,1,2,1,56,1,2,1,1,1,1,4,1,1,

%U 1,1,2,1,56,1,2,1,1,1,1,4,1,1,1,1,2,1,56,1,2,1,1,1

%N Continued fraction for sqrt(825).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_14">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,0,0,0,0,0,0,1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(825)),confrac);

%t ContinuedFraction[Sqrt[825],100] (* _Harvey P. Dale_, Sep 28 2012 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.