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Continued fraction for sqrt(623).
1

%I #19 Jan 03 2024 03:00:23

%S 24,1,23,1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,23,

%T 1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,

%U 23,1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,23,1,48,1,23

%N Continued fraction for sqrt(623).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,1).

%F From _Amiram Eldar_, Jan 03 2024: (Start)

%F Multiplicative with a(2) = 23, a(2^e) = 48 for e >= 2, and a(p^e) = 1 for an odd prime p.

%F Dirichlet g.f.: zeta(s) * (1 + 11/2^(s-1) + 25/2^(2*s)). (End)

%p with(numtheory): Digits := 300: convert(evalf(sqrt(623)),confrac);

%t ContinuedFraction[Sqrt[623], 100] (* _Amiram Eldar_, Jan 03 2024 *)

%K nonn,cofr,easy,mult,less

%O 0,1

%A _N. J. A. Sloane_