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%I #17 Dec 27 2023 00:55:53
%S 23,1,1,1,1,1,4,1,1,1,1,1,46,1,1,1,1,1,4,1,1,1,1,1,46,1,1,1,1,1,4,1,1,
%T 1,1,1,46,1,1,1,1,1,4,1,1,1,1,1,46,1,1,1,1,1,4,1,1,1,1,1,46,1,1,1,1,1,
%U 4,1,1,1,1,1,46,1,1,1,1,1,4,1,1,1,1,1,46,1,1,1,1,1
%N Continued fraction for sqrt(558).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(558)),confrac);
%t ContinuedFraction[Sqrt[558],120] (* or *) PadRight[{23},120,{46,1,1,1,1,1,4,1,1,1,1,1}] (* _Harvey P. Dale_, Apr 22 2022 *)
%K nonn,cofr,easy,less
%O 0,1
%A _N. J. A. Sloane_.