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%I #11 Mar 10 2017 09:42:32
%S 19,6,2,1,3,1,1,2,1,12,19,12,1,2,1,1,3,1,2,6,38,6,2,1,3,1,1,2,1,12,19,
%T 12,1,2,1,1,3,1,2,6,38,6,2,1,3,1,1,2,1,12,19,12,1,2,1,1,3,1,2,6,38,6,
%U 2,1,3,1,1,2,1,12,19,12,1,2,1,1,3,1,2,6,38,6,2,1,3,1
%N Continued fraction for sqrt(367).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_20">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(367)),confrac);
%t ContinuedFraction[Sqrt[367],90] (* _Harvey P. Dale_, Oct 19 2012 *)
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_.
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