%I #16 Dec 27 2023 00:02:34
%S 19,7,1,1,1,2,12,2,1,1,1,7,38,7,1,1,1,2,12,2,1,1,1,7,38,7,1,1,1,2,12,
%T 2,1,1,1,7,38,7,1,1,1,2,12,2,1,1,1,7,38,7,1,1,1,2,12,2,1,1,1,7,38,7,1,
%U 1,1,2,12,2,1,1,1,7,38,7,1,1,1,2,12,2,1,1,1,7,38,7,1
%N Continued fraction for sqrt(366).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).
%p with(numtheory): Digits := 300: convert(evalf(sqrt(366)),confrac);
%t ContinuedFraction[Sqrt[366],100] (* _Harvey P. Dale_, Oct 18 2013 *)
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_.