%I #19 Dec 10 2023 01:51:21
%S 16,1,15,1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,15,
%T 1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,
%U 15,1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,15,1,32,1,15
%N Continued fraction for sqrt(287).
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.
%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,1).
%F From _Amiram Eldar_, Dec 10 2023: (Start)
%F Multiplicative with a(2) = 15, a(2^e) = 32 for e >= 2, and a(p^e) = 1 for p >= 5.
%F Dirichlet g.f.: zeta(s) * (1 + 7/2^(s-1) + 17/4^s). (End)
%p with(numtheory): Digits := 300: convert(evalf(sqrt(287)),confrac);
%t ContinuedFraction[Sqrt[287],120] (* or *) PadRight[{16},120,{32,1,15,1}] (* _Harvey P. Dale_, Sep 15 2017 *)
%K nonn,cofr,easy,mult
%O 0,1
%A _N. J. A. Sloane_
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