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A040265 Continued fraction for sqrt(282). 1

%I #18 Dec 10 2023 01:51:09

%S 16,1,3,1,4,1,3,1,32,1,3,1,4,1,3,1,32,1,3,1,4,1,3,1,32,1,3,1,4,1,3,1,

%T 32,1,3,1,4,1,3,1,32,1,3,1,4,1,3,1,32,1,3,1,4,1,3,1,32,1,3,1,4,1,3,1,

%U 32,1,3,1,4,1,3,1,32,1,3,1,4,1,3,1,32,1,3,1,4,1,3,1

%N Continued fraction for sqrt(282).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,1).

%F From _Amiram Eldar_, Dec 09 2023: (Start)

%F Multiplicative with a(2) = 3, a(4) = 4, a(2^e) = 32 for e >= 3, and a(p^e) = 1 for an odd prime p.

%F Dirichlet g.f.: zeta(s) * (1 + 1/2^(s-1) + 1/2^(2*s) + 7/2^(3*s-2)). (End)

%p with(numtheory): Digits := 300: convert(evalf(sqrt(282)),confrac);

%t ContinuedFraction[Sqrt[282], 100] (* _Amiram Eldar_, Dec 09 2023 *)

%K nonn,cofr,easy,mult

%O 0,1

%A _N. J. A. Sloane_

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