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Continued fraction for sqrt(261).
0

%I #16 Dec 27 2023 00:01:07

%S 16,6,2,3,7,1,3,1,2,1,3,1,7,3,2,6,32,6,2,3,7,1,3,1,2,1,3,1,7,3,2,6,32,

%T 6,2,3,7,1,3,1,2,1,3,1,7,3,2,6,32,6,2,3,7,1,3,1,2,1,3,1,7,3,2,6,32,6,

%U 2,3,7,1,3,1,2,1,3,1,7,3,2,6,32,6,2,3,7,1,3,1,2,1

%N Continued fraction for sqrt(261).

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_16">Index entries for linear recurrences with constant coefficients</a>, signature (0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1).

%p with(numtheory): Digits := 300: convert(evalf(sqrt(261)),confrac);

%t ContinuedFraction[Sqrt[261],120] (* or *) PadRight[{16},120,{32,6,2,3,7,1,3,1,2,1,3,1,7,3,2,6}] (* _Harvey P. Dale_, Feb 25 2018 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_.